x^2+18x=143

Solution for x^2+18x=143 equation:

x^2+18x=143

We move all terms to the left:

x^2+18x-(143)=0

a = 1; b = 18; c = -143;
Δ = b2-4ac
Δ = 182-4·1·(-143)
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-8\sqrt{14}}{2*1}=\frac{-18-8\sqrt{14}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+8\sqrt{14}}{2*1}=\frac{-18+8\sqrt{14}}{2}
$